Jaroslav

Cheers,

Adam

t1,t2,t3 etc are each switching points (either on or off, alternating for each one). The parameter is the length of time for that switching period. The sequence either repeats or ends (based on the repeat parameter) when the following switching period parameter is less that the previous. Does this sound correct?

Assuming my understanding above is correct, to give a blink at 5hz (which I would understand as 5 blinks per second, with 5 equal length none blinks in-between), assuming the BIS timing is independent of the task tick, y0 =on t1=0.1 t2=0.1 t3-t8=0 would give a 5hz blink, and would be clearer to me what is happening.

Not exactly. All the parameters are in seconds and they are relative to the start (let's say t0) when Y0 is applied. Now when the elapsed time since t0 is equal to t1, the output is switched. When it is equal to t2, it is switched again, etc. So for a 5 Hz blink you should set Y0=on, t1=0.1, t2=0.2, t3=0, RPT=on. Because t3<t2, the sequence ends at t2. The remaining parameters t4..t8 are ignored. And because RPT=on, at t2 a new t0 is set, Y0 is applied and the sequence is generated again.

You are absolutely right. I'll improve that.

Hope it's more clear now. If not, I'll be happy to help.

Jaroslav

Thank you once again, I now think I understand but just to make it totally clear in my head and possibly others:

t1,t2,t3 etc are each switching points (either on or off, alternating for each one). The parameter is the length of time for that switching period. The sequence either repeats or ends (based on the repeat parameter) when the following switching period parameter is less that the previous. Does this sound correct?

A few related questions and points I have are:

I am presuming parameters t4-t8 are all 0 in your example?

I am also presuming the parameter does not relates to the tick of that task, or does it; i.e. if the t1 parameter is 2, and the tick of the task is 1 execution per second, the t1 switching period lasts 2 seconds?

I think the explanation in the documentation for the BIS block could do with a little bit of improvement, maybe a bit more clarification and the example you have put in your post above.

I also don't think the example in the blink tutorial really explains how the BIS block works very clearly. Assuming my understanding above is correct, to give a blink at 5hz (which I would understand as 5 blinks per second, with 5 equal length none blinks in-between), assuming the BIS timing is independent of the task tick, y0 =on t1=0.1 t2=0.1 t3-t8=0 would give a 5hz blink, and would be clearer to me what is happening.

Thanks again for your help,

Adam

This is what you should obtain:

Hope I got your question right.

Jaroslav

Cheers,

Adam

Am I trying to do something that this block is not designed for?

Is there any other documentation that I can look at to try and understand how it works; for example is the block based on something from somewhere else?

Is anyone able to explain how I can configure it to get the outputs I am looking for?

Thanks,

Adam